Solve R=0.40/2+3^2/8(0.40)

$$R = \frac { 0.40 } { 2 } + \frac { 3 ^ { 2 } } { 8 ( 0.40 ) }$$

Solve for R

$$R=3.0125$$

Steps for Solving Linear Equation

Expand \frac{0.4}{2} by multiplying both numerator and the denominator by 10.

$$R=\frac{4}{20}+\frac{3^{2}}{8\times 0.4}$$

Reduce the fraction \frac{4}{20} to lowest terms by extracting and canceling out 4.

$$R=\frac{1}{5}+\frac{3^{2}}{8\times 0.4}$$

Calculate 3 to the power of 2 and get 9.

$$R=\frac{1}{5}+\frac{9}{8\times 0.4}$$

Multiply 8 and 0.4 to get 3.2.

$$R=\frac{1}{5}+\frac{9}{3.2}$$

Expand \frac{9}{3.2} by multiplying both numerator and the denominator by 10.

$$R=\frac{1}{5}+\frac{90}{32}$$

Reduce the fraction \frac{90}{32} to lowest terms by extracting and canceling out 2.

$$R=\frac{1}{5}+\frac{45}{16}$$

Least common multiple of 5 and 16 is 80. Convert \frac{1}{5} and \frac{45}{16} to fractions with denominator 80.

$$R=\frac{16}{80}+\frac{225}{80}$$

Since \frac{16}{80} and \frac{225}{80} have the same denominator, add them by adding their numerators.

$$R=\frac{16+225}{80}$$

Add 16 and 225 to get 241.

$$R=\frac{241}{80}$$

Assign R

$$R≔3.0125$$