Solve R=frac{-2^{2}+(1/3)^-2}{-2^4+(-2)^2+4^0}

$$R = \frac { - 2 ^ { 2 } + ( \frac { 1 } { 3 } ) ^ { - 2 } } { - 2 ^ { 4 } + ( - 2 ) ^ { 2 } + 4 ^ { 0 } }$$

Solve for R

$$R=-\frac{5}{11}\approx -0.454545455$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$R=\frac{-4+\left(\frac{1}{3}\right)^{-2}}{-2^{4}+\left(-2\right)^{2}+4^{0}}$$

Calculate \frac{1}{3} to the power of -2 and get 9.

$$R=\frac{-4+9}{-2^{4}+\left(-2\right)^{2}+4^{0}}$$

Add -4 and 9 to get 5.

$$R=\frac{5}{-2^{4}+\left(-2\right)^{2}+4^{0}}$$

Calculate 2 to the power of 4 and get 16.

$$R=\frac{5}{-16+\left(-2\right)^{2}+4^{0}}$$

Calculate -2 to the power of 2 and get 4.

$$R=\frac{5}{-16+4+4^{0}}$$

Add -16 and 4 to get -12.

$$R=\frac{5}{-12+4^{0}}$$

Calculate 4 to the power of 0 and get 1.

$$R=\frac{5}{-12+1}$$

Add -12 and 1 to get -11.

$$R=\frac{5}{-11}$$

Fraction \frac{5}{-11} can be rewritten as -\frac{5}{11} by extracting the negative sign.

$$R=-\frac{5}{11}$$

Assign R

$$R≔-\frac{5}{11}$$