Solve P_{1}=P_{2}e^-bu

$$P _ { 1 } = P _ { 2 } e ^ { - b u }$$

Solve for P_2

$$P_{2}=P_{1}e^{bu}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$P_{2}e^{\left(-b\right)u}=P_{1}$$

Reorder the terms.

$$P_{2}e^{-bu}=P_{1}$$

The equation is in standard form.

$$\frac{1}{e^{bu}}P_{2}=P_{1}$$

Divide both sides by e^{-bu}.

$$\frac{\frac{1}{e^{bu}}P_{2}e^{bu}}{1}=\frac{P_{1}e^{bu}}{1}$$

Dividing by e^{-bu} undoes the multiplication by e^{-bu}.

$$P_{2}=\frac{P_{1}e^{bu}}{1}$$

Divide P_{1} by e^{-bu}.

$$P_{2}=P_{1}e^{bu}$$

Solve for P_1

$$P_{1}=\frac{P_{2}}{e^{bu}}$$