Solve P(x)=x^50-1;x+1=0

$$P ( x ) = x ^ { 50 } - 1 ; x + 1 = 0$$

Solve for P, x

$$x=-1$$

$$P=0$$

Solution Steps

Consider the second equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$x=-1$$

Consider the first equation. Insert the known values of variables into the equation.

$$P\left(-1\right)=\left(-1\right)^{50}-1$$

Calculate -1 to the power of 50 and get 1.

$$P\left(-1\right)=1-1$$

Subtract 1 from 1 to get 0.

$$P\left(-1\right)=0$$

Divide both sides by -1. Zero divided by any non-zero number gives zero.

$$P=0$$

The system is now solved.

$$P=0 x=-1$$