Solve P(n)=2m^2-3m^2+2m^2+m

$$P ( n ) = 2 m ^ { 2 } - 3 m ^ { 2 } + 2 m ^ { 2 } + m$$

Evaluate

$$m\left(m+1\right)$$

Solution Steps

Combine 2m^{2} and -3m^{2} to get -m^{2}.

$$-m^{2}+2m^{2}+m$$

Combine -m^{2} and 2m^{2} to get m^{2}.

$$m^{2}+m$$

Factor

$$m\left(m+1\right)$$

Solution Steps

Factor out m.

$$m\left(2m-3m+2m+1\right)$$

Consider 2m-3m+2m+1. Multiply and combine like terms.

$$m+1$$

Rewrite the complete factored expression.

$$m\left(m+1\right)$$