Solve P(2)=2*(2)^5-m*(2)^4+11*(2)^3-6*(2)^2-m*2-2=0

$$P ( 2 ) = 2 \cdot ( 2 ) ^ { 5 } - m \cdot ( 2 ) ^ { 4 } + 11 \cdot ( 2 ) ^ { 3 } - 6 \cdot ( 2 ) ^ { 2 } - m \cdot 2 - 2 = 0$$

Solve for m

$$m=7$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 1 and 5 to get 6.

$$2^{6}-m\times 2^{4}+11\times 2^{3}-6\times 2^{2}-m\times 2-2=0$$

Calculate 2 to the power of 6 and get 64.

$$64-m\times 2^{4}+11\times 2^{3}-6\times 2^{2}-m\times 2-2=0$$

Calculate 2 to the power of 4 and get 16.

$$64-m\times 16+11\times 2^{3}-6\times 2^{2}-m\times 2-2=0$$

Calculate 2 to the power of 3 and get 8.

$$64-m\times 16+11\times 8-6\times 2^{2}-m\times 2-2=0$$

Multiply 11 and 8 to get 88.

$$64-m\times 16+88-6\times 2^{2}-m\times 2-2=0$$

Calculate 2 to the power of 2 and get 4.

$$64-m\times 16+88-6\times 4-m\times 2-2=0$$

Multiply 6 and 4 to get 24.

$$64-m\times 16+88-24-m\times 2-2=0$$

Subtract 24 from 88 to get 64.

$$64-m\times 16+64-m\times 2-2=0$$

Add 2 to both sides. Anything plus zero gives itself.

$$64-m\times 16+64-m\times 2=2$$

Multiply -1 and 16 to get -16.

$$64-16m+64-m\times 2=2$$

Add 64 and 64 to get 128.

$$128-16m-m\times 2=2$$

Multiply -1 and 2 to get -2.

$$128-16m-2m=2$$

Combine -16m and -2m to get -18m.

$$128-18m=2$$

Subtract 128 from both sides.

$$-18m=2-128$$

Subtract 128 from 2 to get -126.

$$-18m=-126$$

Divide both sides by -18.

$$m=\frac{-126}{-18}$$

Divide -126 by -18 to get 7.

$$m=7$$