Solve P(-1)=2*(-1)^3-3(-1)^2+2(-1)+7

$$P ( - 1 ) = 2 \cdot ( - 1 ) ^ { 3 } - 3 ( - 1 ) ^ { 2 } + 2 ( - 1 ) + 7$$

Evaluate

$$0$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$2\left(-1\right)-3\left(-1\right)^{2}+2\left(-1\right)+7$$

Multiply 2 and -1 to get -2.

$$-2-3\left(-1\right)^{2}+2\left(-1\right)+7$$

Calculate -1 to the power of 2 and get 1.

$$-2-3\times 1+2\left(-1\right)+7$$

Multiply 3 and 1 to get 3.

$$-2-3+2\left(-1\right)+7$$

Subtract 3 from -2 to get -5.

$$-5+2\left(-1\right)+7$$

Multiply 2 and -1 to get -2.

$$-5-2+7$$

Subtract 2 from -5 to get -7.

$$-7+7$$

Add -7 and 7 to get 0.

$$0$$

Factor

$$0$$