Solve P(21/20)^2-p/10=30

$$P ( \frac { 21 } { 20 } ) ^ { 2 } - \frac { p } { 10 } = 30$$

Solve for P

$$P=\frac{40\left(p+300\right)}{441}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 10.

$$10P\times \left(\frac{21}{20}\right)^{2}-p=300$$

Calculate \frac{21}{20} to the power of 2 and get \frac{441}{400}.

$$10P\times \frac{441}{400}-p=300$$

Multiply 10 and \frac{441}{400} to get \frac{441}{40}.

$$\frac{441}{40}P-p=300$$

Add p to both sides.

$$\frac{441}{40}P=300+p$$

The equation is in standard form.

$$\frac{441}{40}P=p+300$$

Divide both sides of the equation by \frac{441}{40}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{441}{40}P}{\frac{441}{40}}=\frac{p+300}{\frac{441}{40}}$$

Dividing by \frac{441}{40} undoes the multiplication by \frac{441}{40}.

$$P=\frac{p+300}{\frac{441}{40}}$$

Divide 300+p by \frac{441}{40} by multiplying 300+p by the reciprocal of \frac{441}{40}.

$$P=\frac{40p}{441}+\frac{4000}{147}$$

Solve for p

$$p=\frac{441P}{40}-300$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 10.

$$10P\times \left(\frac{21}{20}\right)^{2}-p=300$$

Calculate \frac{21}{20} to the power of 2 and get \frac{441}{400}.

$$10P\times \frac{441}{400}-p=300$$

Multiply 10 and \frac{441}{400} to get \frac{441}{40}.

$$\frac{441}{40}P-p=300$$

Subtract \frac{441}{40}P from both sides.

$$-p=300-\frac{441}{40}P$$

The equation is in standard form.

$$-p=-\frac{441P}{40}+300$$

Divide both sides by -1.

$$\frac{-p}{-1}=\frac{-\frac{441P}{40}+300}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$p=\frac{-\frac{441P}{40}+300}{-1}$$

Divide -\frac{441P}{40}+300 by -1.

$$p=\frac{441P}{40}-300$$