Solve for D (complex solution)
\left\{\begin{matrix}D=\frac{42-P}{2Q}\text{, }&Q\neq 0\\D\in \mathrm{C}\text{, }&P=42\text{ and }Q=0\end{matrix}\right.
Solve for D
\left\{\begin{matrix}D=\frac{42-P}{2Q}\text{, }&Q\neq 0\\D\in \mathrm{R}\text{, }&P=42\text{ and }Q=0\end{matrix}\right.
Solve for P
P=42-2DQ
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42-2QD=P
Swap sides so that all variable terms are on the left hand side.
-2QD=P-42
Subtract 42 from both sides.
\left(-2Q\right)D=P-42
The equation is in standard form.
\frac{\left(-2Q\right)D}{-2Q}=\frac{P-42}{-2Q}
Divide both sides by -2Q.
D=\frac{P-42}{-2Q}
Dividing by -2Q undoes the multiplication by -2Q.
D=-\frac{P-42}{2Q}
Divide P-42 by -2Q.
42-2QD=P
Swap sides so that all variable terms are on the left hand side.
-2QD=P-42
Subtract 42 from both sides.
\left(-2Q\right)D=P-42
The equation is in standard form.
\frac{\left(-2Q\right)D}{-2Q}=\frac{P-42}{-2Q}
Divide both sides by -2Q.
D=\frac{P-42}{-2Q}
Dividing by -2Q undoes the multiplication by -2Q.
D=-\frac{P-42}{2Q}
Divide P-42 by -2Q.
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