Solve P=b/2h+b*Po

$$P = \frac { b } { 2 h + b } \times P o$$

Solve for P

$$\left\{\begin{matrix}P=0\text{, }&b\neq -2h\\P\in \mathrm{R}\text{, }&o=\frac{b+2h}{b}\text{ and }b\neq -2h\text{ and }b\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Express \frac{b}{2h+b}P as a single fraction.

$$P=\frac{bP}{2h+b}o$$

Express \frac{bP}{2h+b}o as a single fraction.

$$P=\frac{bPo}{2h+b}$$

Subtract \frac{bPo}{2h+b} from both sides.

$$P-\frac{bPo}{2h+b}=0$$

To add or subtract expressions, expand them to make their denominators the same. Multiply P times \frac{2h+b}{2h+b}.

$$\frac{P\left(2h+b\right)}{2h+b}-\frac{bPo}{2h+b}=0$$

Since \frac{P\left(2h+b\right)}{2h+b} and \frac{bPo}{2h+b} have the same denominator, subtract them by subtracting their numerators.

$$\frac{P\left(2h+b\right)-bPo}{2h+b}=0$$

Do the multiplications in P\left(2h+b\right)-bPo.

$$\frac{2Ph+Pb-bPo}{2h+b}=0$$

Multiply both sides of the equation by b+2h.

$$2Ph+Pb-bPo=0$$

Combine all terms containing P.

$$\left(2h+b-bo\right)P=0$$

Divide 0 by 2h+b-bo.

$$P=0$$

Solve for b

$$\left\{\begin{matrix}b=\frac{2h}{o-1}\text{, }&o\neq 0\text{ and }h\neq 0\text{ and }o\neq 1\\b\neq 0\text{, }&h=0\text{ and }o=1\\b\neq -2h\text{, }&P=0\end{matrix}\right.$$