Solve M_{o}=90+1045-32/(45-32)+(45-38)=

$$M _ { o } = 90 + 10 \frac { 45 - 32 } { ( 45 - 32 ) + ( 45 - 38 ) } =$$

Solve for M_o

$$M_{o} = \frac{193}{2} = 96\frac{1}{2} = 96.5$$

Steps for Solving Linear Equation

Subtract 32 from 45 to get 13.

$$M_{o}=90+10\times \frac{13}{45-32+45-38}$$

Subtract 32 from 45 to get 13.

$$M_{o}=90+10\times \frac{13}{13+45-38}$$

Add 13 and 45 to get 58.

$$M_{o}=90+10\times \frac{13}{58-38}$$

Subtract 38 from 58 to get 20.

$$M_{o}=90+10\times \frac{13}{20}$$

Express 10\times \frac{13}{20} as a single fraction.

$$M_{o}=90+\frac{10\times 13}{20}$$

Multiply 10 and 13 to get 130.

$$M_{o}=90+\frac{130}{20}$$

Reduce the fraction \frac{130}{20} to lowest terms by extracting and canceling out 10.

$$M_{o}=90+\frac{13}{2}$$

Convert 90 to fraction \frac{180}{2}.

$$M_{o}=\frac{180}{2}+\frac{13}{2}$$

Since \frac{180}{2} and \frac{13}{2} have the same denominator, add them by adding their numerators.

$$M_{o}=\frac{180+13}{2}$$

Add 180 and 13 to get 193.

$$M_{o}=\frac{193}{2}$$

Assign M_o

$$M_{o}≔\frac{193}{2}$$