Solve M(65)=-1/28(65)^2+3(65)-31

$$M ( 65 ) = - \frac { 1 } { 28 } ( 65 ) ^ { 2 } + 3 ( 65 ) - 31$$

Evaluate

$$\frac{367}{28}\approx 13.107142857$$

Solution Steps

Calculate 65 to the power of 2 and get 4225.

$$-\frac{1}{28}\times 4225+3\times 65-31$$

Express -\frac{1}{28}\times 4225 as a single fraction.

$$\frac{-4225}{28}+3\times 65-31$$

Fraction \frac{-4225}{28} can be rewritten as -\frac{4225}{28} by extracting the negative sign.

$$-\frac{4225}{28}+3\times 65-31$$

Multiply 3 and 65 to get 195.

$$-\frac{4225}{28}+195-31$$

Convert 195 to fraction \frac{5460}{28}.

$$-\frac{4225}{28}+\frac{5460}{28}-31$$

Since -\frac{4225}{28} and \frac{5460}{28} have the same denominator, add them by adding their numerators.

$$\frac{-4225+5460}{28}-31$$

Add -4225 and 5460 to get 1235.

$$\frac{1235}{28}-31$$

Convert 31 to fraction \frac{868}{28}.

$$\frac{1235}{28}-\frac{868}{28}$$

Since \frac{1235}{28} and \frac{868}{28} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1235-868}{28}$$

Subtract 868 from 1235 to get 367.

$$\frac{367}{28}$$

Factor

$$\frac{367}{2 ^ {2} \cdot 7} = 13\frac{3}{28} = 13.107142857142858$$