Solve M=1-2/3/2+frac{1{3}}

$$M = \frac { 1 - \frac { 2 } { 3 } } { 2 + \frac { 1 } { 3 } }$$

Solve for M

$$M=\frac{1}{7}\approx 0.142857143$$

Steps for Solving Linear Equation

Convert 1 to fraction \frac{3}{3}.

$$M=\frac{\frac{3}{3}-\frac{2}{3}}{2+\frac{1}{3}}$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$M=\frac{\frac{3-2}{3}}{2+\frac{1}{3}}$$

Subtract 2 from 3 to get 1.

$$M=\frac{\frac{1}{3}}{2+\frac{1}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$M=\frac{\frac{1}{3}}{\frac{6}{3}+\frac{1}{3}}$$

Since \frac{6}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$M=\frac{\frac{1}{3}}{\frac{6+1}{3}}$$

Add 6 and 1 to get 7.

$$M=\frac{\frac{1}{3}}{\frac{7}{3}}$$

Divide \frac{1}{3} by \frac{7}{3} by multiplying \frac{1}{3} by the reciprocal of \frac{7}{3}.

$$M=\frac{1}{3}\times \frac{3}{7}$$

Multiply \frac{1}{3} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.

$$M=\frac{1\times 3}{3\times 7}$$

Cancel out 3 in both numerator and denominator.

$$M=\frac{1}{7}$$

Assign M

$$M≔\frac{1}{7}$$