Solve M/B=q*l^2/8

$$M / B = \frac { q \cdot l ^ { 2 } } { 8 }$$

Solve for B

$$\left\{\begin{matrix}B=\frac{8M}{ql^{2}}\text{, }&M\neq 0\text{ and }l\neq 0\text{ and }q\neq 0\\B\neq 0\text{, }&\left(q=0\text{ or }l=0\right)\text{ and }M=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable B cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8B, the least common multiple of B,8.

$$8M=Bql^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$Bql^{2}=8M$$

The equation is in standard form.

$$ql^{2}B=8M$$

Divide both sides by ql^{2}.

$$\frac{ql^{2}B}{ql^{2}}=\frac{8M}{ql^{2}}$$

Dividing by ql^{2} undoes the multiplication by ql^{2}.

$$B=\frac{8M}{ql^{2}}$$

Variable B cannot be equal to 0.

$$B=\frac{8M}{ql^{2}}\text{, }B\neq 0$$

Solve for M

$$M=\frac{Bql^{2}}{8}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8B, the least common multiple of B,8.

$$8M=Bql^{2}$$

Divide both sides by 8.

$$\frac{8M}{8}=\frac{Bql^{2}}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$M=\frac{Bql^{2}}{8}$$