Solve L_{2}:6x+10y-7=0?

$$L _ { 2 } : 6 x + 10 y - 7 = 0 ?$$

Solve for L_2 (complex solution)

$$\left\{\begin{matrix}L_{2}=-\frac{6\left(10y-7\right)}{x}\text{, }&x\neq 0\\L_{2}\in \mathrm{C}\text{, }&y=\frac{7}{10}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$L_{2}x+60y-42=0$$

Subtract 60y from both sides. Anything subtracted from zero gives its negation.

$$L_{2}x-42=-60y$$

Add 42 to both sides.

$$L_{2}x=-60y+42$$

The equation is in standard form.

$$xL_{2}=42-60y$$

Divide both sides by x.

$$\frac{xL_{2}}{x}=\frac{42-60y}{x}$$

Dividing by x undoes the multiplication by x.

$$L_{2}=\frac{42-60y}{x}$$

Divide -60y+42 by x.

$$L_{2}=\frac{6\left(7-10y\right)}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{6\left(10y-7\right)}{L_{2}}\text{, }&L_{2}\neq 0\\x\in \mathrm{C}\text{, }&y=\frac{7}{10}\text{ and }L_{2}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$L_{2}x+60y-42=0$$

Subtract 60y from both sides. Anything subtracted from zero gives its negation.

$$L_{2}x-42=-60y$$

Add 42 to both sides.

$$L_{2}x=-60y+42$$

The equation is in standard form.

$$L_{2}x=42-60y$$

Divide both sides by L_{2}.

$$\frac{L_{2}x}{L_{2}}=\frac{42-60y}{L_{2}}$$

Dividing by L_{2} undoes the multiplication by L_{2}.

$$x=\frac{42-60y}{L_{2}}$$

Divide -60y+42 by L_{2}.

$$x=\frac{6\left(7-10y\right)}{L_{2}}$$

Solve for L_2

$$\left\{\begin{matrix}L_{2}=-\frac{6\left(10y-7\right)}{x}\text{, }&x\neq 0\\L_{2}\in \mathrm{R}\text{, }&y=\frac{7}{10}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$L_{2}x+60y-42=0$$

Subtract 60y from both sides. Anything subtracted from zero gives its negation.

$$L_{2}x-42=-60y$$

Add 42 to both sides.

$$L_{2}x=-60y+42$$

The equation is in standard form.

$$xL_{2}=42-60y$$

Divide both sides by x.

$$\frac{xL_{2}}{x}=\frac{42-60y}{x}$$

Dividing by x undoes the multiplication by x.

$$L_{2}=\frac{42-60y}{x}$$

Divide -60y+42 by x.

$$L_{2}=\frac{6\left(7-10y\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{6\left(10y-7\right)}{L_{2}}\text{, }&L_{2}\neq 0\\x\in \mathrm{R}\text{, }&y=\frac{7}{10}\text{ and }L_{2}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$L_{2}x+60y-42=0$$

Subtract 60y from both sides. Anything subtracted from zero gives its negation.

$$L_{2}x-42=-60y$$

Add 42 to both sides.

$$L_{2}x=-60y+42$$

The equation is in standard form.

$$L_{2}x=42-60y$$

Divide both sides by L_{2}.

$$\frac{L_{2}x}{L_{2}}=\frac{42-60y}{L_{2}}$$

Dividing by L_{2} undoes the multiplication by L_{2}.

$$x=\frac{42-60y}{L_{2}}$$

Divide -60y+42 by L_{2}.

$$x=\frac{6\left(7-10y\right)}{L_{2}}$$