Solve L^2dt=1

$$L ^ { 2 } d t = 1$$

Solve for d

$$d=\frac{1}{tL^{2}}$$

$$t\neq 0\text{ and }L\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$tL^{2}d=1$$

Divide both sides by L^{2}t.

$$\frac{tL^{2}d}{tL^{2}}=\frac{1}{tL^{2}}$$

Dividing by L^{2}t undoes the multiplication by L^{2}t.

$$d=\frac{1}{tL^{2}}$$

Solve for L (complex solution)

$$L=-d^{-\frac{1}{2}}t^{-\frac{1}{2}}$$

$$L=d^{-\frac{1}{2}}t^{-\frac{1}{2}}\text{, }t\neq 0\text{ and }d\neq 0$$

Solve for L

$$L=\frac{1}{\sqrt{dt}}$$

$$L=-\frac{1}{\sqrt{dt}}\text{, }\left(t>0\text{ and }d>0\right)\text{ or }\left(d<0\text{ and }t<0\right)$$