Solve for c
c=8L-5d
Solve for L
L=\frac{c+5d}{8}
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L=\frac{1}{8}c+\frac{5}{8}d
Divide each term of c+5d by 8 to get \frac{1}{8}c+\frac{5}{8}d.
\frac{1}{8}c+\frac{5}{8}d=L
Swap sides so that all variable terms are on the left hand side.
\frac{1}{8}c=L-\frac{5}{8}d
Subtract \frac{5}{8}d from both sides.
\frac{1}{8}c=-\frac{5d}{8}+L
The equation is in standard form.
\frac{\frac{1}{8}c}{\frac{1}{8}}=\frac{-\frac{5d}{8}+L}{\frac{1}{8}}
Multiply both sides by 8.
c=\frac{-\frac{5d}{8}+L}{\frac{1}{8}}
Dividing by \frac{1}{8} undoes the multiplication by \frac{1}{8}.
c=8L-5d
Divide L-\frac{5d}{8} by \frac{1}{8} by multiplying L-\frac{5d}{8} by the reciprocal of \frac{1}{8}.
L=\frac{1}{8}c+\frac{5}{8}d
Divide each term of c+5d by 8 to get \frac{1}{8}c+\frac{5}{8}d.
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