Solve for b
b=2L+c
Solve for L
L=\frac{b-c}{2}
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L=\frac{1}{2}b-\frac{1}{2}c
Divide each term of b-c by 2 to get \frac{1}{2}b-\frac{1}{2}c.
\frac{1}{2}b-\frac{1}{2}c=L
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}b=L+\frac{1}{2}c
Add \frac{1}{2}c to both sides.
\frac{1}{2}b=\frac{c}{2}+L
The equation is in standard form.
\frac{\frac{1}{2}b}{\frac{1}{2}}=\frac{\frac{c}{2}+L}{\frac{1}{2}}
Multiply both sides by 2.
b=\frac{\frac{c}{2}+L}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
b=2L+c
Divide L+\frac{c}{2} by \frac{1}{2} by multiplying L+\frac{c}{2} by the reciprocal of \frac{1}{2}.
L=\frac{1}{2}b-\frac{1}{2}c
Divide each term of b-c by 2 to get \frac{1}{2}b-\frac{1}{2}c.
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