Solve KL=sqrt{[-2-(-6)]^2+(4-2)^2}=

$$K L = \sqrt { [ - 2 - ( - 6 ) ] ^ { 2 } + ( 4 - 2 ) ^ { 2 } } =$$

Solve for K

$$K=\frac{2\sqrt{5}}{L}$$

$$L\neq 0$$

Steps for Solving Linear Equation

The opposite of -6 is 6.

$$KL=\sqrt{\left(-2+6\right)^{2}+\left(4-2\right)^{2}}$$

Add -2 and 6 to get 4.

$$KL=\sqrt{4^{2}+\left(4-2\right)^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$KL=\sqrt{16+\left(4-2\right)^{2}}$$

Subtract 2 from 4 to get 2.

$$KL=\sqrt{16+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$KL=\sqrt{16+4}$$

Add 16 and 4 to get 20.

$$KL=\sqrt{20}$$

Factor 20=2^{2}\times 5. Rewrite the square root of the product \sqrt{2^{2}\times 5} as the product of square roots \sqrt{2^{2}}\sqrt{5}. Take the square root of 2^{2}.

$$KL=2\sqrt{5}$$

The equation is in standard form.

$$LK=2\sqrt{5}$$

Divide both sides by L.

$$\frac{LK}{L}=\frac{2\sqrt{5}}{L}$$

Dividing by L undoes the multiplication by L.

$$K=\frac{2\sqrt{5}}{L}$$

Solve for L

$$L=\frac{2\sqrt{5}}{K}$$

$$K\neq 0$$

Steps for Solving Linear Equation

The opposite of -6 is 6.

$$KL=\sqrt{\left(-2+6\right)^{2}+\left(4-2\right)^{2}}$$

Add -2 and 6 to get 4.

$$KL=\sqrt{4^{2}+\left(4-2\right)^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$KL=\sqrt{16+\left(4-2\right)^{2}}$$

Subtract 2 from 4 to get 2.

$$KL=\sqrt{16+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$KL=\sqrt{16+4}$$

Add 16 and 4 to get 20.

$$KL=\sqrt{20}$$

Factor 20=2^{2}\times 5. Rewrite the square root of the product \sqrt{2^{2}\times 5} as the product of square roots \sqrt{2^{2}}\sqrt{5}. Take the square root of 2^{2}.

$$KL=2\sqrt{5}$$

Divide both sides by K.

$$\frac{KL}{K}=\frac{2\sqrt{5}}{K}$$

Dividing by K undoes the multiplication by K.

$$L=\frac{2\sqrt{5}}{K}$$