Solve KA=2y/K^2M

$$K A = \frac { 2 y } { K ^ { 2 } } M$$

Solve for A

$$A=\frac{2My}{K^{3}}$$

$$K\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by K^{2}.

$$KAK^{2}=2yM$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$K^{3}A=2yM$$

The equation is in standard form.

$$K^{3}A=2My$$

Divide both sides by K^{3}.

$$\frac{K^{3}A}{K^{3}}=\frac{2My}{K^{3}}$$

Dividing by K^{3} undoes the multiplication by K^{3}.

$$A=\frac{2My}{K^{3}}$$

Solve for K

$$\left\{\begin{matrix}K=\sqrt[3]{\frac{2My}{A}}\text{, }&M\neq 0\text{ and }y\neq 0\text{ and }A\neq 0\\K\neq 0\text{, }&\left(y=0\text{ or }M=0\right)\text{ and }A=0\end{matrix}\right.$$