Skip to main content
Solve for K
Tick mark Image

Similar Problems from Web Search

Share

K^{2}=\frac{9\left(16-12\times 16\right)^{2}}{5\times 16\times 16\times 20}
Cancel out 4 in both numerator and denominator.
K^{2}=\frac{9\left(16-192\right)^{2}}{5\times 16\times 16\times 20}
Multiply 12 and 16 to get 192.
K^{2}=\frac{9\left(-176\right)^{2}}{5\times 16\times 16\times 20}
Subtract 192 from 16 to get -176.
K^{2}=\frac{9\times 30976}{5\times 16\times 16\times 20}
Calculate -176 to the power of 2 and get 30976.
K^{2}=\frac{278784}{5\times 16\times 16\times 20}
Multiply 9 and 30976 to get 278784.
K^{2}=\frac{278784}{80\times 16\times 20}
Multiply 5 and 16 to get 80.
K^{2}=\frac{278784}{1280\times 20}
Multiply 80 and 16 to get 1280.
K^{2}=\frac{278784}{25600}
Multiply 1280 and 20 to get 25600.
K^{2}=\frac{1089}{100}
Reduce the fraction \frac{278784}{25600} to lowest terms by extracting and canceling out 256.
K^{2}-\frac{1089}{100}=0
Subtract \frac{1089}{100} from both sides.
100K^{2}-1089=0
Multiply both sides by 100.
\left(10K-33\right)\left(10K+33\right)=0
Consider 100K^{2}-1089. Rewrite 100K^{2}-1089 as \left(10K\right)^{2}-33^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
K=\frac{33}{10} K=-\frac{33}{10}
To find equation solutions, solve 10K-33=0 and 10K+33=0.
K^{2}=\frac{9\left(16-12\times 16\right)^{2}}{5\times 16\times 16\times 20}
Cancel out 4 in both numerator and denominator.
K^{2}=\frac{9\left(16-192\right)^{2}}{5\times 16\times 16\times 20}
Multiply 12 and 16 to get 192.
K^{2}=\frac{9\left(-176\right)^{2}}{5\times 16\times 16\times 20}
Subtract 192 from 16 to get -176.
K^{2}=\frac{9\times 30976}{5\times 16\times 16\times 20}
Calculate -176 to the power of 2 and get 30976.
K^{2}=\frac{278784}{5\times 16\times 16\times 20}
Multiply 9 and 30976 to get 278784.
K^{2}=\frac{278784}{80\times 16\times 20}
Multiply 5 and 16 to get 80.
K^{2}=\frac{278784}{1280\times 20}
Multiply 80 and 16 to get 1280.
K^{2}=\frac{278784}{25600}
Multiply 1280 and 20 to get 25600.
K^{2}=\frac{1089}{100}
Reduce the fraction \frac{278784}{25600} to lowest terms by extracting and canceling out 256.
K=\frac{33}{10} K=-\frac{33}{10}
Take the square root of both sides of the equation.
K^{2}=\frac{9\left(16-12\times 16\right)^{2}}{5\times 16\times 16\times 20}
Cancel out 4 in both numerator and denominator.
K^{2}=\frac{9\left(16-192\right)^{2}}{5\times 16\times 16\times 20}
Multiply 12 and 16 to get 192.
K^{2}=\frac{9\left(-176\right)^{2}}{5\times 16\times 16\times 20}
Subtract 192 from 16 to get -176.
K^{2}=\frac{9\times 30976}{5\times 16\times 16\times 20}
Calculate -176 to the power of 2 and get 30976.
K^{2}=\frac{278784}{5\times 16\times 16\times 20}
Multiply 9 and 30976 to get 278784.
K^{2}=\frac{278784}{80\times 16\times 20}
Multiply 5 and 16 to get 80.
K^{2}=\frac{278784}{1280\times 20}
Multiply 80 and 16 to get 1280.
K^{2}=\frac{278784}{25600}
Multiply 1280 and 20 to get 25600.
K^{2}=\frac{1089}{100}
Reduce the fraction \frac{278784}{25600} to lowest terms by extracting and canceling out 256.
K^{2}-\frac{1089}{100}=0
Subtract \frac{1089}{100} from both sides.
K=\frac{0±\sqrt{0^{2}-4\left(-\frac{1089}{100}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{1089}{100} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
K=\frac{0±\sqrt{-4\left(-\frac{1089}{100}\right)}}{2}
Square 0.
K=\frac{0±\sqrt{\frac{1089}{25}}}{2}
Multiply -4 times -\frac{1089}{100}.
K=\frac{0±\frac{33}{5}}{2}
Take the square root of \frac{1089}{25}.
K=\frac{33}{10}
Now solve the equation K=\frac{0±\frac{33}{5}}{2} when ± is plus.
K=-\frac{33}{10}
Now solve the equation K=\frac{0±\frac{33}{5}}{2} when ± is minus.
K=\frac{33}{10} K=-\frac{33}{10}
The equation is now solved.