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Solve for I_n
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xI_{n}=x+8
The equation is in standard form.
\frac{xI_{n}}{x}=\frac{x+8}{x}
Divide both sides by x.
I_{n}=\frac{x+8}{x}
Dividing by x undoes the multiplication by x.
I_{n}x-x=8
Subtract x from both sides.
\left(I_{n}-1\right)x=8
Combine all terms containing x.
\frac{\left(I_{n}-1\right)x}{I_{n}-1}=\frac{8}{I_{n}-1}
Divide both sides by I_{n}-1.
x=\frac{8}{I_{n}-1}
Dividing by I_{n}-1 undoes the multiplication by I_{n}-1.