Solve for I_P
I_{P}=0.02
Assign I_P
I_{P}≔0.02
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I_{P}=\frac{4.8}{240}
Multiply 0.4 and 12 to get 4.8.
I_{P}=\frac{48}{2400}
Expand \frac{4.8}{240} by multiplying both numerator and the denominator by 10.
I_{P}=\frac{1}{50}
Reduce the fraction \frac{48}{2400} to lowest terms by extracting and canceling out 48.
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