Solve I_{I}+0.40(100-x)=50

$$I _ { I } + 0.40 ( 100 - x ) = 50$$

Solve for I_I

$$I_{I}=\frac{2x}{5}+10$$

Solution Steps

Use the distributive property to multiply 0.4 by 100-x.

$$I_{I}+40-0.4x=50$$

Subtract 40 from both sides.

$$I_{I}-0.4x=50-40$$

Subtract 40 from 50 to get 10.

$$I_{I}-0.4x=10$$

Add 0.4x to both sides.

$$I_{I}=10+0.4x$$

Solve for x

$$x=\frac{5I_{I}}{2}-25$$

Steps for Solving Linear Equation

Use the distributive property to multiply 0.4 by 100-x.

$$I_{I}+40-0.4x=50$$

Subtract I_{I} from both sides.

$$40-0.4x=50-I_{I}$$

Subtract 40 from both sides.

$$-0.4x=50-I_{I}-40$$

Subtract 40 from 50 to get 10.

$$-0.4x=10-I_{I}$$

Divide both sides of the equation by -0.4, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-0.4x}{-0.4}=\frac{10-I_{I}}{-0.4}$$

Dividing by -0.4 undoes the multiplication by -0.4.

$$x=\frac{10-I_{I}}{-0.4}$$

Divide 10-I_{I} by -0.4 by multiplying 10-I_{I} by the reciprocal of -0.4.

$$x=\frac{5I_{I}}{2}-25$$