Solve I_{D}=1/2(1*10^-3)(-2-(-1))^2

$$I _ { D } = \frac { 1 } { 2 } ( 1 \cdot 10 ^ { - 3 } ) ( - 2 - ( - 1 ) ) ^ { 2 }$$

Solve for I_D

$$I_{D}=\frac{1}{2000}=0.0005$$

Steps for Solving Linear Equation

Multiply \frac{1}{2} and 1 to get \frac{1}{2}.

$$I_{D}=\frac{1}{2}\times 10^{-3}\left(-2-\left(-1\right)\right)^{2}$$

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$I_{D}=\frac{1}{2}\times \frac{1}{1000}\left(-2-\left(-1\right)\right)^{2}$$

Multiply \frac{1}{2} and \frac{1}{1000} to get \frac{1}{2000}.

$$I_{D}=\frac{1}{2000}\left(-2-\left(-1\right)\right)^{2}$$

The opposite of -1 is 1.

$$I_{D}=\frac{1}{2000}\left(-2+1\right)^{2}$$

Add -2 and 1 to get -1.

$$I_{D}=\frac{1}{2000}\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$I_{D}=\frac{1}{2000}\times 1$$

Multiply \frac{1}{2000} and 1 to get \frac{1}{2000}.

$$I_{D}=\frac{1}{2000}$$

Assign I_D

$$I_{D}≔\frac{1}{2000}$$