Solve I_{3}*20+I_{1}*10=60

$$I _ { 3 } \times 20 + I _ { 1 } \times 10 = 60$$

Solve for I_1

$$I_{1}=6-2I_{3}$$

Steps for Solving Linear Equation

Subtract I_{3}\times 20 from both sides.

$$I_{1}\times 10=60-I_{3}\times 20$$

Multiply -1 and 20 to get -20.

$$I_{1}\times 10=60-20I_{3}$$

The equation is in standard form.

$$10I_{1}=60-20I_{3}$$

Divide both sides by 10.

$$\frac{10I_{1}}{10}=\frac{60-20I_{3}}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$I_{1}=\frac{60-20I_{3}}{10}$$

Divide 60-20I_{3} by 10.

$$I_{1}=6-2I_{3}$$

Solve for I_3

$$I_{3}=-\frac{I_{1}}{2}+3$$

Steps for Solving Linear Equation

Subtract I_{1}\times 10 from both sides.

$$I_{3}\times 20=60-I_{1}\times 10$$

Multiply -1 and 10 to get -10.

$$I_{3}\times 20=60-10I_{1}$$

The equation is in standard form.

$$20I_{3}=60-10I_{1}$$

Divide both sides by 20.

$$\frac{20I_{3}}{20}=\frac{60-10I_{1}}{20}$$

Dividing by 20 undoes the multiplication by 20.

$$I_{3}=\frac{60-10I_{1}}{20}$$

Divide 60-10I_{1} by 20.

$$I_{3}=-\frac{I_{1}}{2}+3$$