Solve for I
I = \frac{71}{6} = 11\frac{5}{6} \approx 11.833333333
Assign I
I≔\frac{71}{6}
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I=\frac{54+1}{6}+\frac{2\times 6+4}{6}
Multiply 9 and 6 to get 54.
I=\frac{55}{6}+\frac{2\times 6+4}{6}
Add 54 and 1 to get 55.
I=\frac{55}{6}+\frac{12+4}{6}
Multiply 2 and 6 to get 12.
I=\frac{55}{6}+\frac{16}{6}
Add 12 and 4 to get 16.
I=\frac{55}{6}+\frac{8}{3}
Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.
I=\frac{55}{6}+\frac{16}{6}
Least common multiple of 6 and 3 is 6. Convert \frac{55}{6} and \frac{8}{3} to fractions with denominator 6.
I=\frac{55+16}{6}
Since \frac{55}{6} and \frac{16}{6} have the same denominator, add them by adding their numerators.
I=\frac{71}{6}
Add 55 and 16 to get 71.
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