Solve I=1/2bh^3

$$I = \frac { 1 } { 2 } b h ^ { 3 }$$

Solve for b

$$\left\{\begin{matrix}b=\frac{2I}{h^{3}}\text{, }&h\neq 0\\b\in \mathrm{R}\text{, }&I=0\text{ and }h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}bh^{3}=I$$

The equation is in standard form.

$$\frac{h^{3}}{2}b=I$$

Divide both sides by \frac{1}{2}h^{3}.

$$\frac{2\times \frac{h^{3}}{2}b}{h^{3}}=\frac{2I}{h^{3}}$$

Dividing by \frac{1}{2}h^{3} undoes the multiplication by \frac{1}{2}h^{3}.

$$b=\frac{2I}{h^{3}}$$

Solve for I

$$I=\frac{bh^{3}}{2}$$