Solve I=100left(1220^2/24^2-02right)

$$I = 100 \left( 12 \frac{ { 20 }^{ 2 } }{ { 24 }^{ 2 } } -02 \right)$$

Solve for I

$$I = \frac{2500}{3} = 833\frac{1}{3} \approx 833.333333333$$

Steps for Solving Linear Equation

Calculate 20 to the power of 2 and get 400.

$$I=100\left(12\times \frac{400}{24^{2}}-0\times 2\right)$$

Calculate 24 to the power of 2 and get 576.

$$I=100\left(12\times \frac{400}{576}-0\times 2\right)$$

Reduce the fraction \frac{400}{576} to lowest terms by extracting and canceling out 16.

$$I=100\left(12\times \frac{25}{36}-0\times 2\right)$$

Express 12\times \frac{25}{36} as a single fraction.

$$I=100\left(\frac{12\times 25}{36}-0\times 2\right)$$

Multiply 12 and 25 to get 300.

$$I=100\left(\frac{300}{36}-0\times 2\right)$$

Reduce the fraction \frac{300}{36} to lowest terms by extracting and canceling out 12.

$$I=100\left(\frac{25}{3}-0\times 2\right)$$

Multiply 0 and 2 to get 0.

$$I=100\left(\frac{25}{3}-0\right)$$

Subtract 0 from \frac{25}{3} to get \frac{25}{3}.

$$I=100\times \frac{25}{3}$$

Express 100\times \frac{25}{3} as a single fraction.

$$I=\frac{100\times 25}{3}$$

Multiply 100 and 25 to get 2500.

$$I=\frac{2500}{3}$$

Assign I

$$I≔\frac{2500}{3}$$