Solve I=100left(1.220^2/25^2-0.2right)

$$I = 100 \left( 1.2 \frac{ { 20 }^{ 2 } }{ { 25 }^{ 2 } } -0.2 \right)$$

Solve for I

$$I=56.8$$

Steps for Solving Linear Equation

Calculate 20 to the power of 2 and get 400.

$$I=100\left(1.2\times \frac{400}{25^{2}}-0.2\right)$$

Calculate 25 to the power of 2 and get 625.

$$I=100\left(1.2\times \frac{400}{625}-0.2\right)$$

Reduce the fraction \frac{400}{625} to lowest terms by extracting and canceling out 25.

$$I=100\left(1.2\times \frac{16}{25}-0.2\right)$$

Convert decimal number 1.2 to fraction \frac{12}{10}. Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$I=100\left(\frac{6}{5}\times \frac{16}{25}-0.2\right)$$

Multiply \frac{6}{5} times \frac{16}{25} by multiplying numerator times numerator and denominator times denominator.

$$I=100\left(\frac{6\times 16}{5\times 25}-0.2\right)$$

Do the multiplications in the fraction \frac{6\times 16}{5\times 25}.

$$I=100\left(\frac{96}{125}-0.2\right)$$

Convert decimal number 0.2 to fraction \frac{2}{10}. Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$I=100\left(\frac{96}{125}-\frac{1}{5}\right)$$

Least common multiple of 125 and 5 is 125. Convert \frac{96}{125} and \frac{1}{5} to fractions with denominator 125.

$$I=100\left(\frac{96}{125}-\frac{25}{125}\right)$$

Since \frac{96}{125} and \frac{25}{125} have the same denominator, subtract them by subtracting their numerators.

$$I=100\times \frac{96-25}{125}$$

Subtract 25 from 96 to get 71.

$$I=100\times \frac{71}{125}$$

Express 100\times \frac{71}{125} as a single fraction.

$$I=\frac{100\times 71}{125}$$

Multiply 100 and 71 to get 7100.

$$I=\frac{7100}{125}$$

Reduce the fraction \frac{7100}{125} to lowest terms by extracting and canceling out 25.

$$I=\frac{284}{5}$$

Assign I

$$I≔56.8$$