Solve I=100left(1.220^2/24^2-0.2right)

$$I = 100 \left( 1.2 \frac{ { 20 }^{ 2 } }{ { 24 }^{ 2 } } -0.2 \right)$$

Solve for I

$$I = \frac{190}{3} = 63\frac{1}{3} \approx 63.333333333$$

Steps for Solving Linear Equation

Calculate 20 to the power of 2 and get 400.

$$I=100\left(1.2\times \frac{400}{24^{2}}-0.2\right)$$

Calculate 24 to the power of 2 and get 576.

$$I=100\left(1.2\times \frac{400}{576}-0.2\right)$$

Reduce the fraction \frac{400}{576} to lowest terms by extracting and canceling out 16.

$$I=100\left(1.2\times \frac{25}{36}-0.2\right)$$

Convert decimal number 1.2 to fraction \frac{12}{10}. Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$I=100\left(\frac{6}{5}\times \frac{25}{36}-0.2\right)$$

Multiply \frac{6}{5} times \frac{25}{36} by multiplying numerator times numerator and denominator times denominator.

$$I=100\left(\frac{6\times 25}{5\times 36}-0.2\right)$$

Do the multiplications in the fraction \frac{6\times 25}{5\times 36}.

$$I=100\left(\frac{150}{180}-0.2\right)$$

Reduce the fraction \frac{150}{180} to lowest terms by extracting and canceling out 30.

$$I=100\left(\frac{5}{6}-0.2\right)$$

Convert decimal number 0.2 to fraction \frac{2}{10}. Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$I=100\left(\frac{5}{6}-\frac{1}{5}\right)$$

Least common multiple of 6 and 5 is 30. Convert \frac{5}{6} and \frac{1}{5} to fractions with denominator 30.

$$I=100\left(\frac{25}{30}-\frac{6}{30}\right)$$

Since \frac{25}{30} and \frac{6}{30} have the same denominator, subtract them by subtracting their numerators.

$$I=100\times \frac{25-6}{30}$$

Subtract 6 from 25 to get 19.

$$I=100\times \frac{19}{30}$$

Express 100\times \frac{19}{30} as a single fraction.

$$I=\frac{100\times 19}{30}$$

Multiply 100 and 19 to get 1900.

$$I=\frac{1900}{30}$$

Reduce the fraction \frac{1900}{30} to lowest terms by extracting and canceling out 10.

$$I=\frac{190}{3}$$

Assign I

$$I≔\frac{190}{3}$$