Solve HB=100%/100%+25%*Hj

$$H B = \frac { 100 \% } { 100 \% + 25 \% } \times H j$$

Solve for B (complex solution)

$$\left\{\begin{matrix}\\B=\frac{4j}{5}\text{, }&\text{unconditionally}\\B\in \mathrm{C}\text{, }&H=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Divide 100 by 100 to get 1.

$$HB=\frac{1}{\frac{100}{100}+\frac{25}{100}}Hj$$

Divide 100 by 100 to get 1.

$$HB=\frac{1}{1+\frac{25}{100}}Hj$$

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$HB=\frac{1}{1+\frac{1}{4}}Hj$$

Add 1 and \frac{1}{4} to get \frac{5}{4}.

$$HB=\frac{1}{\frac{5}{4}}Hj$$

Divide 1 by \frac{5}{4} by multiplying 1 by the reciprocal of \frac{5}{4}.

$$HB=1\times \frac{4}{5}Hj$$

Multiply 1 and \frac{4}{5} to get \frac{4}{5}.

$$HB=\frac{4}{5}Hj$$

The equation is in standard form.

$$HB=\frac{4Hj}{5}$$

Divide both sides by H.

$$\frac{HB}{H}=\frac{4Hj}{5H}$$

Dividing by H undoes the multiplication by H.

$$B=\frac{4Hj}{5H}$$

Divide \frac{4Hj}{5} by H.

$$B=\frac{4j}{5}$$

Solve for H (complex solution)

$$\left\{\begin{matrix}\\H=0\text{, }&\text{unconditionally}\\H\in \mathrm{C}\text{, }&B=\frac{4j}{5}\end{matrix}\right.$$

Steps for Solving Linear Equation

Divide 100 by 100 to get 1.

$$HB=\frac{1}{\frac{100}{100}+\frac{25}{100}}Hj$$

Divide 100 by 100 to get 1.

$$HB=\frac{1}{1+\frac{25}{100}}Hj$$

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$HB=\frac{1}{1+\frac{1}{4}}Hj$$

Add 1 and \frac{1}{4} to get \frac{5}{4}.

$$HB=\frac{1}{\frac{5}{4}}Hj$$

Divide 1 by \frac{5}{4} by multiplying 1 by the reciprocal of \frac{5}{4}.

$$HB=1\times \frac{4}{5}Hj$$

Multiply 1 and \frac{4}{5} to get \frac{4}{5}.

$$HB=\frac{4}{5}Hj$$

Subtract \frac{4}{5}Hj from both sides.

$$HB-\frac{4}{5}Hj=0$$

Combine all terms containing H.

$$\left(B-\frac{4}{5}j\right)H=0$$

The equation is in standard form.

$$\left(-\frac{4j}{5}+B\right)H=0$$

Divide 0 by B-\frac{4}{5}j.

$$H=0$$

Solve for B

$$\left\{\begin{matrix}\\B=\frac{4j}{5}\text{, }&\text{unconditionally}\\B\in \mathrm{R}\text{, }&H=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Divide 100 by 100 to get 1.

$$HB=\frac{1}{\frac{100}{100}+\frac{25}{100}}Hj$$

Divide 100 by 100 to get 1.

$$HB=\frac{1}{1+\frac{25}{100}}Hj$$

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$HB=\frac{1}{1+\frac{1}{4}}Hj$$

Add 1 and \frac{1}{4} to get \frac{5}{4}.

$$HB=\frac{1}{\frac{5}{4}}Hj$$

Divide 1 by \frac{5}{4} by multiplying 1 by the reciprocal of \frac{5}{4}.

$$HB=1\times \frac{4}{5}Hj$$

Multiply 1 and \frac{4}{5} to get \frac{4}{5}.

$$HB=\frac{4}{5}Hj$$

The equation is in standard form.

$$HB=\frac{4Hj}{5}$$

Divide both sides by H.

$$\frac{HB}{H}=\frac{4Hj}{5H}$$

Dividing by H undoes the multiplication by H.

$$B=\frac{4Hj}{5H}$$

Divide \frac{4Hj}{5} by H.

$$B=\frac{4j}{5}$$

Solve for H

$$\left\{\begin{matrix}\\H=0\text{, }&\text{unconditionally}\\H\in \mathrm{R}\text{, }&B=\frac{4j}{5}\end{matrix}\right.$$

Steps for Solving Linear Equation

Divide 100 by 100 to get 1.

$$HB=\frac{1}{\frac{100}{100}+\frac{25}{100}}Hj$$

Divide 100 by 100 to get 1.

$$HB=\frac{1}{1+\frac{25}{100}}Hj$$

Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$HB=\frac{1}{1+\frac{1}{4}}Hj$$

Add 1 and \frac{1}{4} to get \frac{5}{4}.

$$HB=\frac{1}{\frac{5}{4}}Hj$$

Divide 1 by \frac{5}{4} by multiplying 1 by the reciprocal of \frac{5}{4}.

$$HB=1\times \frac{4}{5}Hj$$

Multiply 1 and \frac{4}{5} to get \frac{4}{5}.

$$HB=\frac{4}{5}Hj$$

Subtract \frac{4}{5}Hj from both sides.

$$HB-\frac{4}{5}Hj=0$$

Combine all terms containing H.

$$\left(B-\frac{4}{5}j\right)H=0$$

The equation is in standard form.

$$\left(-\frac{4j}{5}+B\right)H=0$$

Divide 0 by B-\frac{4}{5}j.

$$H=0$$