Solve H=25/21+8/7+4/3=

$$H = \frac { 25 } { 21 } + \frac { 8 } { 7 } + \frac { 4 } { 3 } =$$

Solve for H

$$H = \frac{11}{3} = 3\frac{2}{3} \approx 3.666666667$$

Steps for Solving Linear Equation

Least common multiple of 21 and 7 is 21. Convert \frac{25}{21} and \frac{8}{7} to fractions with denominator 21.

$$H=\frac{25}{21}+\frac{24}{21}+\frac{4}{3}$$

Since \frac{25}{21} and \frac{24}{21} have the same denominator, add them by adding their numerators.

$$H=\frac{25+24}{21}+\frac{4}{3}$$

Add 25 and 24 to get 49.

$$H=\frac{49}{21}+\frac{4}{3}$$

Reduce the fraction \frac{49}{21} to lowest terms by extracting and canceling out 7.

$$H=\frac{7}{3}+\frac{4}{3}$$

Since \frac{7}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$H=\frac{7+4}{3}$$

Add 7 and 4 to get 11.

$$H=\frac{11}{3}$$

Assign H

$$H≔\frac{11}{3}$$