Solve for G
G=\frac{9R}{\left(4R+3\right)^{2}}
R\neq -0.75
Solve for R
\left\{\begin{matrix}\\R=0\text{, }&\text{unconditionally}\\R=\frac{-\frac{3G}{2}+\sqrt{-\frac{27G}{16}+0.31640625}+0.5625}{2G}\text{; }R=\frac{-\frac{3G}{2}-\sqrt{-\frac{27G}{16}+0.31640625}+0.5625}{2G}\text{, }&G\neq 0\text{ and }G\leq 0.1875\end{matrix}\right.
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