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xF=2x^{2}+x-15
The equation is in standard form.
\frac{xF}{x}=\frac{\left(2x-5\right)\left(x+3\right)}{x}
Divide both sides by x.
F=\frac{\left(2x-5\right)\left(x+3\right)}{x}
Dividing by x undoes the multiplication by x.
F=2x+1-\frac{15}{x}
Divide \left(-5+2x\right)\left(3+x\right) by x.