Solve Fx=-4/3x^2+x-14

$$Fx = \frac{ -4 }{ 3 } { x }^{ 2 } +x-14$$

Solve for F

$$F=-\frac{4x}{3}+1-\frac{14}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$Fx=-\frac{4}{3}x^{2}+x-14$$

The equation is in standard form.

$$xF=-\frac{4x^{2}}{3}+x-14$$

Divide both sides by x.

$$\frac{xF}{x}=\frac{-\frac{4x^{2}}{3}+x-14}{x}$$

Dividing by x undoes the multiplication by x.

$$F=\frac{-\frac{4x^{2}}{3}+x-14}{x}$$

Divide -\frac{4x^{2}}{3}+x-14 by x.

$$F=-\frac{4x}{3}+1-\frac{14}{x}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{9F^{2}-18F-663}-3F+3}{8}$$

$$x=\frac{-\sqrt{9F^{2}-18F-663}-3F+3}{8}$$

Solve for x

$$x=\frac{\sqrt{9F^{2}-18F-663}-3F+3}{8}$$

$$x=\frac{-\sqrt{9F^{2}-18F-663}-3F+3}{8}\text{, }F\geq \frac{4\sqrt{42}}{3}+1\text{ or }F\leq -\frac{4\sqrt{42}}{3}+1$$