Solve for F
F=2x-3+\frac{1}{x}
x\neq 0
Solve for x (complex solution)
x=\frac{-\sqrt{F^{2}+6F+1}+F+3}{4}
x=\frac{\sqrt{F^{2}+6F+1}+F+3}{4}
Solve for x
x=\frac{-\sqrt{F^{2}+6F+1}+F+3}{4}
x=\frac{\sqrt{F^{2}+6F+1}+F+3}{4}\text{, }F\geq 2\sqrt{2}-3\text{ or }F\leq -2\sqrt{2}-3
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xF=2x^{2}-3x+1
The equation is in standard form.
\frac{xF}{x}=\frac{\left(x-1\right)\left(2x-1\right)}{x}
Divide both sides by x.
F=\frac{\left(x-1\right)\left(2x-1\right)}{x}
Dividing by x undoes the multiplication by x.
F=2x-3+\frac{1}{x}
Divide \left(-1+x\right)\left(-1+2x\right) by x.
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