Solve F-32=9/5(c-0)

$$F - 32 = 9 / 5 ( c - 0 )$$

Solve for F

$$F=\frac{9c}{5}+32$$

Solution Steps

Add 32 to both sides.

$$F=\frac{9}{5}\left(c-0\right)+32$$

Reorder the terms.

$$F=\frac{9}{5}c+32$$

Solve for c

$$c=\frac{5\left(F-32\right)}{9}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{9}{5}\left(c-0\right)=F-32$$

Reorder the terms.

$$\frac{9}{5}c=F-32$$

Divide both sides of the equation by \frac{9}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{9}{5}c}{\frac{9}{5}}=\frac{F-32}{\frac{9}{5}}$$

Dividing by \frac{9}{5} undoes the multiplication by \frac{9}{5}.

$$c=\frac{F-32}{\frac{9}{5}}$$

Divide F-32 by \frac{9}{5} by multiplying F-32 by the reciprocal of \frac{9}{5}.

$$c=\frac{5F-160}{9}$$