Solve for F
F=\frac{x+4}{x^{2}}
x\neq 0
Solve for x (complex solution)
\left\{\begin{matrix}x=\frac{\sqrt{16F+1}+1}{2F}\text{; }x=\frac{-\sqrt{16F+1}+1}{2F}\text{, }&F\neq 0\\x=-4\text{, }&F=0\end{matrix}\right.
Solve for x
\left\{\begin{matrix}x=\frac{\sqrt{16F+1}+1}{2F}\text{; }x=\frac{-\sqrt{16F+1}+1}{2F}\text{, }&F\neq 0\text{ and }F\geq -\frac{1}{16}\\x=-4\text{, }&F=0\end{matrix}\right.
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x^{2}F=x+4
The equation is in standard form.
\frac{x^{2}F}{x^{2}}=\frac{x+4}{x^{2}}
Divide both sides by x^{2}.
F=\frac{x+4}{x^{2}}
Dividing by x^{2} undoes the multiplication by x^{2}.
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