F ( x ) = x ^ { 2 } + 1 \quad ( 2,5 )
Solve for F
F=x+\frac{5}{2x}
x\neq 0
Solve for x
x=\frac{-\sqrt{F^{2}-10}+F}{2}
x=\frac{\sqrt{F^{2}-10}+F}{2}\text{, }|F|\geq \sqrt{10}
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Fx=x^{2}+2,5
Multiply 1 and 2,5 to get 2,5.
xF=x^{2}+2,5
The equation is in standard form.
\frac{xF}{x}=\frac{x^{2}+2,5}{x}
Divide both sides by x.
F=\frac{x^{2}+2,5}{x}
Dividing by x undoes the multiplication by x.
F=x+\frac{5}{2x}
Divide x^{2}+2,5 by x.
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