Solve F(x)=3(2)^4-8(2)^2+6(2)+4

$$F ( x ) = 3 ( 2 ) ^ { 4 } - 8 ( 2 ) ^ { 2 } + 6 ( 2 ) + 4$$

Evaluate

$$32$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$3\times 16-8\times 2^{2}+6\times 2+4$$

Multiply 3 and 16 to get 48.

$$48-8\times 2^{2}+6\times 2+4$$

Calculate 2 to the power of 2 and get 4.

$$48-8\times 4+6\times 2+4$$

Multiply 8 and 4 to get 32.

$$48-32+6\times 2+4$$

Subtract 32 from 48 to get 16.

$$16+6\times 2+4$$

Multiply 6 and 2 to get 12.

$$16+12+4$$

Add 16 and 12 to get 28.

$$28+4$$

Add 28 and 4 to get 32.

$$32$$

Factor

$$2^{5}$$