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\frac{-2x^{2}+x+1}{2}
Factor out \frac{1}{2}.
a+b=1 ab=-2=-2
Consider -2x^{2}+x+1. Factor the expression by grouping. First, the expression needs to be rewritten as -2x^{2}+ax+bx+1. To find a and b, set up a system to be solved.
a=2 b=-1
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(-2x^{2}+2x\right)+\left(-x+1\right)
Rewrite -2x^{2}+x+1 as \left(-2x^{2}+2x\right)+\left(-x+1\right).
2x\left(-x+1\right)-x+1
Factor out 2x in -2x^{2}+2x.
\left(-x+1\right)\left(2x+1\right)
Factor out common term -x+1 by using distributive property.
\frac{\left(-x+1\right)\left(2x+1\right)}{2}
Rewrite the complete factored expression.