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Solve for x (complex solution)
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\left(2x+1\right)x=-3\left(x+3\right)
Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.
2x^{2}+x=-3\left(x+3\right)
Use the distributive property to multiply 2x+1 by x.
2x^{2}+x=-3x-9
Use the distributive property to multiply -3 by x+3.
2x^{2}+x+3x=-9
Add 3x to both sides.
2x^{2}+4x=-9
Combine x and 3x to get 4x.
2x^{2}+4x+9=0
Add 9 to both sides.
x=\frac{-4±\sqrt{4^{2}-4\times 2\times 9}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 4 for b, and 9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-4±\sqrt{16-4\times 2\times 9}}{2\times 2}
Square 4.
x=\frac{-4±\sqrt{16-8\times 9}}{2\times 2}
Multiply -4 times 2.
x=\frac{-4±\sqrt{16-72}}{2\times 2}
Multiply -8 times 9.
x=\frac{-4±\sqrt{-56}}{2\times 2}
Add 16 to -72.
x=\frac{-4±2\sqrt{14}i}{2\times 2}
Take the square root of -56.
x=\frac{-4±2\sqrt{14}i}{4}
Multiply 2 times 2.
x=\frac{-4+2\sqrt{14}i}{4}
Now solve the equation x=\frac{-4±2\sqrt{14}i}{4} when ± is plus. Add -4 to 2i\sqrt{14}.
x=\frac{\sqrt{14}i}{2}-1
Divide -4+2i\sqrt{14} by 4.
x=\frac{-2\sqrt{14}i-4}{4}
Now solve the equation x=\frac{-4±2\sqrt{14}i}{4} when ± is minus. Subtract 2i\sqrt{14} from -4.
x=-\frac{\sqrt{14}i}{2}-1
Divide -4-2i\sqrt{14} by 4.
x=\frac{\sqrt{14}i}{2}-1 x=-\frac{\sqrt{14}i}{2}-1
The equation is now solved.
\left(2x+1\right)x=-3\left(x+3\right)
Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.
2x^{2}+x=-3\left(x+3\right)
Use the distributive property to multiply 2x+1 by x.
2x^{2}+x=-3x-9
Use the distributive property to multiply -3 by x+3.
2x^{2}+x+3x=-9
Add 3x to both sides.
2x^{2}+4x=-9
Combine x and 3x to get 4x.
\frac{2x^{2}+4x}{2}=-\frac{9}{2}
Divide both sides by 2.
x^{2}+\frac{4}{2}x=-\frac{9}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}+2x=-\frac{9}{2}
Divide 4 by 2.
x^{2}+2x+1^{2}=-\frac{9}{2}+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=-\frac{9}{2}+1
Square 1.
x^{2}+2x+1=-\frac{7}{2}
Add -\frac{9}{2} to 1.
\left(x+1\right)^{2}=-\frac{7}{2}
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{-\frac{7}{2}}
Take the square root of both sides of the equation.
x+1=\frac{\sqrt{14}i}{2} x+1=-\frac{\sqrt{14}i}{2}
Simplify.
x=\frac{\sqrt{14}i}{2}-1 x=-\frac{\sqrt{14}i}{2}-1
Subtract 1 from both sides of the equation.