Solve F(x)=2/3x^2+1quad[2,2]

$$F ( x ) = \frac { 2 } { 3 } x ^ { 2 } + 1 \quad [ 2,2 ]$$

Solve for F

$$F=\frac{2x}{3}+\frac{11}{5x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply 1 and 2,2 to get 2,2.

$$Fx=\frac{2}{3}x^{2}+2,2$$

The equation is in standard form.

$$xF=\frac{2x^{2}}{3}+2,2$$

Divide both sides by x.

$$\frac{xF}{x}=\frac{\frac{2x^{2}}{3}+\frac{11}{5}}{x}$$

Dividing by x undoes the multiplication by x.

$$F=\frac{\frac{2x^{2}}{3}+\frac{11}{5}}{x}$$

Divide \frac{2x^{2}}{3}+\frac{11}{5} by x.

$$F=\frac{2x}{3}+\frac{11}{5x}$$

Solve for x

$$x=-\frac{\sqrt{225F^{2}-1320}}{20}+\frac{3F}{4}$$

$$x=\frac{\sqrt{225F^{2}-1320}}{20}+\frac{3F}{4}\text{, }|F|\geq \frac{2\sqrt{330}}{15}$$