Solve F(2,836.75)=1-exp(-c*2,836.75^gamma)=0.75

$$F ( 2,836.75 ) = 1 - \exp ( - c \times 2,836.75 ^ { \gamma } ) = 0.75$$

Solve for c

$$c=-\frac{\frac{4}{11347}^{\gamma }}{4epx}$$

$$p\neq 0\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Multiply -1 and -1 to get 1.

$$1+expc\times 2836.75^{\gamma }=0.75$$

Subtract 1 from both sides.

$$expc\times 2836.75^{\gamma }=0.75-1$$

Subtract 1 from 0.75 to get -0.25.

$$expc\times 2836.75^{\gamma }=-0.25$$

The equation is in standard form.

$$epx\times 2836.75^{\gamma }c=-0.25$$

Divide both sides by exp\times 2836.75^{\gamma }.

$$\frac{epx\times 2836.75^{\gamma }c}{epx\times 2836.75^{\gamma }}=-\frac{0.25}{epx\times 2836.75^{\gamma }}$$

Dividing by exp\times 2836.75^{\gamma } undoes the multiplication by exp\times 2836.75^{\gamma }.

$$c=-\frac{0.25}{epx\times 2836.75^{\gamma }}$$

Divide -0.25 by exp\times 2836.75^{\gamma }.

$$c=-\frac{\frac{4}{11347}^{\gamma }}{4epx}$$

Solve for p

$$p=-\frac{\frac{4}{11347}^{\gamma }}{4ecx}$$

$$c\neq 0\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Multiply -1 and -1 to get 1.

$$1+expc\times 2836.75^{\gamma }=0.75$$

Subtract 1 from both sides.

$$expc\times 2836.75^{\gamma }=0.75-1$$

Subtract 1 from 0.75 to get -0.25.

$$expc\times 2836.75^{\gamma }=-0.25$$

The equation is in standard form.

$$ecx\times 2836.75^{\gamma }p=-0.25$$

Divide both sides by exc\times 2836.75^{\gamma }.

$$\frac{ecx\times 2836.75^{\gamma }p}{ecx\times 2836.75^{\gamma }}=-\frac{0.25}{ecx\times 2836.75^{\gamma }}$$

Dividing by exc\times 2836.75^{\gamma } undoes the multiplication by exc\times 2836.75^{\gamma }.

$$p=-\frac{0.25}{ecx\times 2836.75^{\gamma }}$$

Divide -0.25 by exc\times 2836.75^{\gamma }.

$$p=-\frac{\frac{4}{11347}^{\gamma }}{4ecx}$$