Solve for F
F=\frac{1}{7}+\frac{6}{7x}
x\neq 0
Solve for x
x=\frac{6}{7F-1}
F\neq \frac{1}{7}
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7F^{1}x=x+6
Multiply both sides of the equation by 7.
7Fx=x+6
Calculate F to the power of 1 and get F.
7xF=x+6
The equation is in standard form.
\frac{7xF}{7x}=\frac{x+6}{7x}
Divide both sides by 7x.
F=\frac{x+6}{7x}
Dividing by 7x undoes the multiplication by 7x.
F=\frac{1}{7}+\frac{6}{7x}
Divide x+6 by 7x.
7F^{1}x=x+6
Multiply both sides of the equation by 7.
7Fx=x+6
Calculate F to the power of 1 and get F.
7Fx-x=6
Subtract x from both sides.
\left(7F-1\right)x=6
Combine all terms containing x.
\frac{\left(7F-1\right)x}{7F-1}=\frac{6}{7F-1}
Divide both sides by 7F-1.
x=\frac{6}{7F-1}
Dividing by 7F-1 undoes the multiplication by 7F-1.
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