Solve F=operatorname{lcos}θ98/10

$$F = \operatorname { lcos } \theta \frac { 98 } { 10 }$$

Solve for l

$$\left\{\begin{matrix}l=\frac{5F}{49\cos(\theta )}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}\\l\in \mathrm{R}\text{, }&F=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}\end{matrix}\right.$$

Steps for Solving Linear Equation

Reduce the fraction \frac{98}{10} to lowest terms by extracting and canceling out 2.

$$F=l\cos(\theta )\times \frac{49}{5}$$

Swap sides so that all variable terms are on the left hand side.

$$l\cos(\theta )\times \frac{49}{5}=F$$

The equation is in standard form.

$$\frac{49\cos(\theta )}{5}l=F$$

Divide both sides by \frac{49}{5}\cos(\theta ).

$$\frac{5\times \frac{49\cos(\theta )}{5}l}{49\cos(\theta )}=\frac{5F}{49\cos(\theta )}$$

Dividing by \frac{49}{5}\cos(\theta ) undoes the multiplication by \frac{49}{5}\cos(\theta ).

$$l=\frac{5F}{49\cos(\theta )}$$

Solve for F

$$F=\frac{49l\cos(\theta )}{5}$$