Solve F=j+p/2

$$F = \frac { j + p } { 2 }$$

Solve for j

$$j=2F-p$$

Steps for Solving Linear Equation

Divide each term of j+p by 2 to get \frac{1}{2}j+\frac{1}{2}p.

$$F=\frac{1}{2}j+\frac{1}{2}p$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}j+\frac{1}{2}p=F$$

Subtract \frac{1}{2}p from both sides.

$$\frac{1}{2}j=F-\frac{1}{2}p$$

The equation is in standard form.

$$\frac{1}{2}j=-\frac{p}{2}+F$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}j}{\frac{1}{2}}=\frac{-\frac{p}{2}+F}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$j=\frac{-\frac{p}{2}+F}{\frac{1}{2}}$$

Divide F-\frac{p}{2} by \frac{1}{2} by multiplying F-\frac{p}{2} by the reciprocal of \frac{1}{2}.

$$j=2F-p$$

Solve for F

$$F=\frac{p+j}{2}$$

Solution Steps

Divide each term of j+p by 2 to get \frac{1}{2}j+\frac{1}{2}p.

$$F=\frac{1}{2}j+\frac{1}{2}p$$