Solve for c
c=\frac{5\left(F-32\right)}{9}
Solve for F
F=\frac{9c}{5}+32
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F=\frac{9}{5}c+32
Divide each term of 9c+160 by 5 to get \frac{9}{5}c+32.
\frac{9}{5}c+32=F
Swap sides so that all variable terms are on the left hand side.
\frac{9}{5}c=F-32
Subtract 32 from both sides.
\frac{\frac{9}{5}c}{\frac{9}{5}}=\frac{F-32}{\frac{9}{5}}
Divide both sides of the equation by \frac{9}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
c=\frac{F-32}{\frac{9}{5}}
Dividing by \frac{9}{5} undoes the multiplication by \frac{9}{5}.
c=\frac{5F-160}{9}
Divide F-32 by \frac{9}{5} by multiplying F-32 by the reciprocal of \frac{9}{5}.
F=\frac{9}{5}c+32
Divide each term of 9c+160 by 5 to get \frac{9}{5}c+32.
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