Solve for B (complex solution)
\left\{\begin{matrix}B=\frac{4F}{3C}\text{, }&C\neq 0\\B\in \mathrm{C}\text{, }&F=0\text{ and }C=0\end{matrix}\right.
Solve for C (complex solution)
\left\{\begin{matrix}C=\frac{4F}{3B}\text{, }&B\neq 0\\C\in \mathrm{C}\text{, }&F=0\text{ and }B=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=\frac{4F}{3C}\text{, }&C\neq 0\\B\in \mathrm{R}\text{, }&F=0\text{ and }C=0\end{matrix}\right.
Solve for C
\left\{\begin{matrix}C=\frac{4F}{3B}\text{, }&B\neq 0\\C\in \mathrm{R}\text{, }&F=0\text{ and }B=0\end{matrix}\right.
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\frac{3}{4}BC=F
Swap sides so that all variable terms are on the left hand side.
\frac{3C}{4}B=F
The equation is in standard form.
\frac{4\times \frac{3C}{4}B}{3C}=\frac{4F}{3C}
Divide both sides by \frac{3}{4}C.
B=\frac{4F}{3C}
Dividing by \frac{3}{4}C undoes the multiplication by \frac{3}{4}C.
\frac{3}{4}BC=F
Swap sides so that all variable terms are on the left hand side.
\frac{3B}{4}C=F
The equation is in standard form.
\frac{4\times \frac{3B}{4}C}{3B}=\frac{4F}{3B}
Divide both sides by \frac{3}{4}B.
C=\frac{4F}{3B}
Dividing by \frac{3}{4}B undoes the multiplication by \frac{3}{4}B.
\frac{3}{4}BC=F
Swap sides so that all variable terms are on the left hand side.
\frac{3C}{4}B=F
The equation is in standard form.
\frac{4\times \frac{3C}{4}B}{3C}=\frac{4F}{3C}
Divide both sides by \frac{3}{4}C.
B=\frac{4F}{3C}
Dividing by \frac{3}{4}C undoes the multiplication by \frac{3}{4}C.
\frac{3}{4}BC=F
Swap sides so that all variable terms are on the left hand side.
\frac{3B}{4}C=F
The equation is in standard form.
\frac{4\times \frac{3B}{4}C}{3B}=\frac{4F}{3B}
Divide both sides by \frac{3}{4}B.
C=\frac{4F}{3B}
Dividing by \frac{3}{4}B undoes the multiplication by \frac{3}{4}B.
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